2/x-3-3/x^2-9

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Solution for 2/x-3-3/x^2-9 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x-(3/(x^2))-9-3 = 0

2/x-3*x^-2-9-3 = 0

2*x^-1-3*x^-2-12 = 0

t_1 = x^-1

2*t_1^1-3*t_1^2-12 = 0

2*t_1-3*t_1^2-12 = 0

DELTA = 2^2-(-12*(-3)*4)

DELTA = -140

DELTA < 0

x belongs to the empty set

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